What is the domain of y=(x^4-16)/(x^2-49) ?

The domain of y=(x^4-16)/(x^2-49) is x 7

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domain of y=(x^4-16)/(x^2-49)

domain

y = \frac{x ^{4} - 16}{x ^{2} - 49}

x < - 7 or - 7 < x < 7 or x > 7

Interval Notation

(- \infty, - 7) \cup (- 7, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 7

The function domain

x < - 7 or - 7 < x < 7 or x > 7

y = x^{2} - 2

x e^{a x}

y = sec (θ)

h (x) = lo g_{2} (x^{2} - 5 x + 6)

What is the domain of y=(x^4-16)/(x^2-49) ?
The domain of y=(x^4-16)/(x^2-49) is x<-7\lor-7<x<7\lor x>7