What is the domain of y=sqrt(x^2-2) ?

The domain of y=sqrt(x^2-2) is x = sqrt(2)

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domain of y=sqrt(x^2-2)

domain

y = x^{2} - 2

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

x e^{a x}

y = sec (θ)

h (x) = lo g_{2} (x^{2} - 5 x + 6)

f (x) = \frac{x ^{2} - 25}{x ^{2} + 81}

What is the domain of y=sqrt(x^2-2) ?
The domain of y=sqrt(x^2-2) is x<=-sqrt(2)\lor x>= sqrt(2)