What is the domain of f(x)=(sqrt(x^2-25))/(x^2+81) ?

The domain of f(x)=(sqrt(x^2-25))/(x^2+81) is x = 5

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domain of f(x)=(sqrt(x^2-25))/(x^2+81)

domain

f (x) = \frac{x ^{2} - 25}{x ^{2} + 81}

x \leq - 5 or x \geq 5

Interval Notation

(- \infty, - 5] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 5 or x \geq 5

The function domain

x \leq - 5 or x \geq 5

\frac{5 x}{x - 1}

f (x) = \frac{x ^{2} + x + 1}{x - 3 + 2 x}

- lo g_{2} (x - 2)

f (x) = \frac{x + 1}{x - 2}

f (x) = \frac{1}{( 3 x ^{2} + 17 x - 6 )}

What is the domain of f(x)=(sqrt(x^2-25))/(x^2+81) ?
The domain of f(x)=(sqrt(x^2-25))/(x^2+81) is x<=-5\lor x>= 5