What is the domain of f(x)=log_{3}((1+y)^2)-2 ?

The domain of f(x)=log_{3}((1+y)^2)-2 is y -1

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domain of f(x)=log_{3}((1+y)^2)-2

domain

f (x) = lo g_{3} ((1 + y)^{2}) - 2

y < - 1 or y > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find positive values for logs:

y < - 1 or y > - 1

The function domain

y < - 1 or y > - 1

f (x) = x - 1 - \frac{1}{2 - x}

g (x) = 4 - 4 x + x^{2}

\frac{2 x + 1}{3}

f (x) = \frac{2 x + 4}{x ^{2} + 3 x - 40}

f (x) = \frac{2 x - 7}{3 x + 5}

What is the domain of f(x)=log_{3}((1+y)^2)-2 ?
The domain of f(x)=log_{3}((1+y)^2)-2 is y<-1\lor y>-1