What is the domain of sqrt(x^2+6) ?

The domain of sqrt(x^2+6) is -infinity <x<infinity

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domain of sqrt(x^2+6)

domain

x^{2} + 6

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = (x^{2} + x) \cdot (x^{2} - 1)^{- 1}

f (x) = \frac{5 x - 2}{7 x + 14}

\frac{x - 1}{x ^{2} + 4 x - 5}

- lo g_{5} (x + 2)

f (x) = \frac{2}{x ^{2} - x - 6}

What is the domain of sqrt(x^2+6) ?
The domain of sqrt(x^2+6) is -infinity <x<infinity