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Popular >

extreme f(x)=x^2-12x+43

Solution

extreme points

f (x) = x^{2} - 12 x + 43

Solution

Minimum (6, 7)

Solution steps

f^{'} (x) = 2 x - 12

Find intervals:

Decreasing

: - \infty < x < 6,

Increasing

: 6 < x < \infty

Plug

x = 6

into

x^{2} - 12 x + 43 : 7

Minimum (6, 7)

Popular Examples

intercepts of f(x)=x^3+3x^2+3x+2 intercepts

f (x) = x^{3} + 3 x^{2} + 3 x + 2

range of y=1+5sec(4x)range

y = 1 + 5 sec (4 x)

slope of 1/4 x-3 slope

\frac{1}{4} x - 3

domain of f(x)=sqrt(x^2-4x)domain

f (x) = x^{2} - 4 x

slope ofintercept 4x-5y=-1 slope intercept

4 x - 5 y = - 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2-12x+43 ?
The extreme f(x)=x^2-12x+43 is Minimum(6,7)