What is the domain of f(x)=(ln(x+2))/(x-3) ?

The domain of f(x)=(ln(x+2))/(x-3) is -2 3

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domain of f(x)=(ln(x+2))/(x-3)

domain

f (x) = \frac{ln ( x + 2 )}{x - 3}

- 2 < x < 3 or x > 3

Interval Notation

(- 2, 3) \cup (3, \infty)

Solution steps

Find positive values for logs:

x > - 2

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

- 2 < x < 3 or x > 3

\frac{4 x}{7 x - 3}

- 5 x + 3

f (x) = x (x - 3)^{\frac{1}{4}}

f (x) = \frac{ln ( x + 2 )}{x - 1}

f (x) = - ∣ x ∣ + 1

What is the domain of f(x)=(ln(x+2))/(x-3) ?
The domain of f(x)=(ln(x+2))/(x-3) is -2<x<3\lor x>3