What is the domain of (sqrt(x^2-4))/(x-3) ?

The domain of (sqrt(x^2-4))/(x-3) is x 3

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domain of (sqrt(x^2-4))/(x-3)

domain

\frac{x ^{2} - 4}{x - 3}

x \leq - 2 or 2 \leq x < 3 or x > 3

Interval Notation

(- \infty, - 2] \cup [2, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x \leq - 2 or 2 \leq x < 3 or x > 3

f (x) = \frac{( 1 - x )}{x}

\frac{6 x}{( x - 5 ) ( x - 9 )}

f (x) = 5^{x} - 3

f (x) = \frac{1}{x - 4}

\frac{x ^{2} + 5 x + 6}{x + 3}

What is the domain of (sqrt(x^2-4))/(x-3) ?
The domain of (sqrt(x^2-4))/(x-3) is x<=-2\lor 2<= x<3\lor x>3