What is the domain of f(x)= 1/(sqrt(z)) ?

The domain of f(x)= 1/(sqrt(z)) is z>0

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domain of f(x)= 1/(sqrt(z))

domain

f (x) = \frac{1}{z}

z > 0

Solution steps

Find non-negative values for radicals:

z \geq 0

Find undefined (singularity) points:

z = 0

Combine real regions and undefined points for final function domain

z > 0

f (x) = \frac{x ^{2}}{2} + \frac{1}{x}

f (x) = ln (12 - 5 x^{2})

y = ln (ln (3 x - 14))

y = 3 tan (x)

y = \frac{x ^{2} + x - 38}{x ^{2} - 25}

What is the domain of f(x)= 1/(sqrt(z)) ?
The domain of f(x)= 1/(sqrt(z)) is z>0