What is the domain of y=(2x^2+6x+4)/(-3x-5) ?

The domain of y=(2x^2+6x+4)/(-3x-5) is x -5/3

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domain of y=(2x^2+6x+4)/(-3x-5)

domain

y = \frac{2 x ^{2} + 6 x + 4}{- 3 x - 5}

x < - \frac{5}{3} or x > - \frac{5}{3}

Interval Notation

(- \infty, - \frac{5}{3}) \cup (- \frac{5}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{5}{3}

The function domain

x < - \frac{5}{3} or x > - \frac{5}{3}

\frac{x ^{2} - x - 20}{x ^{2} - x + 2}

f (x) = \frac{x ^{2}}{3 - x}

lo g_{10} (4 x - x^{2})

f (x) = \frac{x}{3 x - 6}

f (x) = \frac{( x - 2 ) ( x + 5 )}{x + 2}

What is the domain of y=(2x^2+6x+4)/(-3x-5) ?
The domain of y=(2x^2+6x+4)/(-3x-5) is x<-5/3 \lor x>-5/3