What is the domain of f(x)=sqrt(x-3)-4 ?

The domain of f(x)=sqrt(x-3)-4 is x>= 3

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domain of f(x)=sqrt(x-3)-4

domain

f (x) = x - 3 - 4

x \geq 3

Interval Notation

[3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

The function domain

x \geq 3

f (x) = lo g_{10} (4 - 2 x)

f (x) = lo g_{10} (16 x - x^{2})

f (x) = \frac{x - 5}{x + 8}

f (x) = - 2 x^{2} - 6 x + 11

f (x) = 35 - 2 x - x^{2} + \frac{1}{x ^{2} - 4}

What is the domain of f(x)=sqrt(x-3)-4 ?
The domain of f(x)=sqrt(x-3)-4 is x>= 3