What is the domain of f(x)=log_{10}(16x-x^2) ?

The domain of f(x)=log_{10}(16x-x^2) is 0<x<16

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domain of f(x)=log_{10}(16x-x^2)

domain

f (x) = lo g_{10} (16 x - x^{2})

0 < x < 16

Solution steps

Find positive values for logs:

0 < x < 16

The function domain

0 < x < 16

f (x) = \frac{x - 5}{x + 8}

f (x) = - 2 x^{2} - 6 x + 11

f (x) = 35 - 2 x - x^{2} + \frac{1}{x ^{2} - 4}

f (x) = lo g_{2 x - 1} (7 - 3 x)

\frac{x ^{3} + 2 x}{x ^{2} + 1}

What is the domain of f(x)=log_{10}(16x-x^2) ?
The domain of f(x)=log_{10}(16x-x^2) is 0<x<16