What is the domain of f(x)=log_{2x-1}(7-3x) ?

The domain of f(x)=log_{2x-1}(7-3x) is 1/2 <x<1\lor 1<x< 7/3

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domain of f(x)=log_{2x-1}(7-3x)

domain

f (x) = lo g_{2 x - 1} (7 - 3 x)

\frac{1}{2} < x < 1 or 1 < x < \frac{7}{3}

Interval Notation

(\frac{1}{2}, 1) \cup (1, \frac{7}{3})

Solution steps

Check logs domain:

\frac{1}{2} < x < 1 or 1 < x < \frac{7}{3}

The function domain

\frac{1}{2} < x < 1 or 1 < x < \frac{7}{3}

\frac{x ^{3} + 2 x}{x ^{2} + 1}

f (x) = x - 5 + 5 - x

56 x^{2} + 13 x - 3

\frac{cos ( x )}{1 + sin ( x )}

f (x) = \frac{1}{5} - x

What is the domain of f(x)=log_{2x-1}(7-3x) ?
The domain of f(x)=log_{2x-1}(7-3x) is 1/2 <x<1\lor 1<x< 7/3