What is the domain of f(x)=sqrt(1/5-x) ?

The domain of f(x)=sqrt(1/5-x) is x<= 1/5

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domain of f(x)=sqrt(1/5-x)

domain

f (x) = \frac{1}{5} - x

x \leq \frac{1}{5}

Solution steps

Find non-negative values for radicals:

x \leq \frac{1}{5}

The function domain

x \leq \frac{1}{5}

f (x) = x 3 - x

f (x) = \frac{x}{( x ^{2} + 1 )}

\frac{2 + 3 x}{x - 1}

f (x) = 4 sin (2 x + 5) - 7

f (x) = \frac{x - 2}{3 x ^{2} + x - 2}

What is the domain of f(x)=sqrt(1/5-x) ?
The domain of f(x)=sqrt(1/5-x) is x<= 1/5