What is the domain of f(x)=(1/2)^{x+1} ?

The domain of f(x)=(1/2)^{x+1} is -infinity <x<infinity

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domain of f(x)=(1/2)^{x+1}

domain

f (x) = (\frac{1}{2})^{x + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

y = \frac{1}{x ^{2} - 5}

f (x) = \frac{x}{x ^{2} - x}

- cos (2 x)

f (x) = 2 x^{2} + 4 x - 3

f (x) = lo g_{2} (x + 1) + lo g_{2} (x - 1)

What is the domain of f(x)=(1/2)^{x+1} ?
The domain of f(x)=(1/2)^{x+1} is -infinity <x<infinity