What is the domain of f(x)=(1-x^2)/x ?

The domain of f(x)=(1-x^2)/x is x 0

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domain of f(x)=(1-x^2)/x

domain

f (x) = \frac{1 - x ^{2}}{x}

x < 0 or x > 0

Interval Notation

(- \infty, 0) \cup (0, \infty)

Solution steps

Find undefined (singularity) points:

x = 0

The function domain

x < 0 or x > 0

f (x) = \frac{x + 2}{x ^{2} - x - 12}

f (x) = \frac{3 x - 2}{8 x + 24}

f (x) = \frac{2}{sin ( 3 x )} + sin (x)

arctan (\frac{1}{x})

χ^{3} - 4 χ

What is the domain of f(x)=(1-x^2)/x ?
The domain of f(x)=(1-x^2)/x is x<0\lor x>0