What is the domain of sqrt(χ^3-4χ) ?

The domain of sqrt(χ^3-4χ) is -2 = 2

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domain of sqrt(χ^3-4χ)

domain

χ^{3} - 4 χ

- 2 \leq χ \leq 0 or χ \geq 2

Interval Notation

[- 2, 0] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

- 2 \leq χ \leq 0 or χ \geq 2

The function domain

- 2 \leq χ \leq 0 or χ \geq 2

f (x) = sin (ln (x))

f (x) = \frac{6 x - 1}{x ^{2} + 1}

4 x^{2}

f (x) = x^{3} - 2 x + 1

f (x) = - (x - 1)^{2} + 4

What is the domain of sqrt(χ^3-4χ) ?
The domain of sqrt(χ^3-4χ) is -2<= χ<= 0\lor χ>= 2