What is the domain of log_{2x-1}(-3x^2+4x+4) ?

The domain of log_{2x-1}(-3x^2+4x+4) is 1/2 <x<1\lor 1<x<2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of log_{2x-1}(-3x^2+4x+4)

domain

lo g_{2 x - 1} (- 3 x^{2} + 4 x + 4)

\frac{1}{2} < x < 1 or 1 < x < 2

Interval Notation

(\frac{1}{2}, 1) \cup (1, 2)

Solution steps

Check logs domain:

\frac{1}{2} < x < 1 or 1 < x < 2

The function domain

\frac{1}{2} < x < 1 or 1 < x < 2

f (x) = \frac{x}{2 - x ^{2}}

f (x) = (x - 3)^{- \frac{1}{4}}

ln (x + 7)

ln (x + 8)

f (x) = \frac{3 x - 2}{3 x + 1}

What is the domain of log_{2x-1}(-3x^2+4x+4) ?
The domain of log_{2x-1}(-3x^2+4x+4) is 1/2 <x<1\lor 1<x<2