What is the domain of f(x)=sqrt(8x-1) ?

The domain of f(x)=sqrt(8x-1) is x>= 1/8

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domain of f(x)=sqrt(8x-1)

domain

f (x) = 8 x - 1

x \geq \frac{1}{8}

Interval Notation

[\frac{1}{8}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{8}

The function domain

x \geq \frac{1}{8}

\frac{x ^{2}}{( x + 2 ) ^{2}}

f (x) = 1 - 16 - x^{2}

sin (4 x)

f (x) = x^{2} + 4 x + 5

f (x) = \frac{2}{5 - 2 x}

What is the domain of f(x)=sqrt(8x-1) ?
The domain of f(x)=sqrt(8x-1) is x>= 1/8