What is the domain of f(x)=sqrt(8x^2-77x+45) ?

The domain of f(x)=sqrt(8x^2-77x+45) is x = 9

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domain of f(x)=sqrt(8x^2-77x+45)

domain

f (x) = 8 x^{2} - 77 x + 45

x \leq \frac{5}{8} or x \geq 9

Interval Notation

(- \infty, \frac{5}{8}] \cup [9, \infty)

Solution steps

Find non-negative values for radicals:

x \leq \frac{5}{8} or x \geq 9

The function domain

x \leq \frac{5}{8} or x \geq 9

f (x) = \frac{2 x ^{2} - 5 x - 12}{x ^{2} - 2 x - 8}

\frac{3 x ^{2} + 5 x - 6}{x ^{2} - 9}

f (x) = \frac{4 x}{x ( x ^{2} - 9 )}

f (x) = ∣ 2 x - 5 ∣

f (x) = 2 x^{2} - 9 x - 5

What is the domain of f(x)=sqrt(8x^2-77x+45) ?
The domain of f(x)=sqrt(8x^2-77x+45) is x<= 5/8 \lor x>= 9