What is the domain of f(x)=(4x)/(x(x^2-9)) ?

The domain of f(x)=(4x)/(x(x^2-9)) is x 3

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domain of f(x)=(4x)/(x(x^2-9))

domain

f (x) = \frac{4 x}{x ( x ^{2} - 9 )}

x < - 3 or - 3 < x < 0 or 0 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 0) \cup (0, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = - 3, x = 3

The function domain

x < - 3 or - 3 < x < 0 or 0 < x < 3 or x > 3

f (x) = ∣ 2 x - 5 ∣

f (x) = 2 x^{2} - 9 x - 5

f (x) = - 4 x + 6 - 15

f (x) = lo g_{2} (x + 1) - 3

x - 2 + 4 - x

What is the domain of f(x)=(4x)/(x(x^2-9)) ?
The domain of f(x)=(4x)/(x(x^2-9)) is x<-3\lor-3<x<0\lor 0<x<3\lor x>3