What is the domain of y=(x^2-36)/(x+1) ?

The domain of y=(x^2-36)/(x+1) is x -1

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domain of y=(x^2-36)/(x+1)

domain

y = \frac{x ^{2} - 36}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

g (x) = lo g_{3} (8 - 2 x) + 1

f (x) = \frac{2 x + 4}{24 - 8 x}

f (x) = \frac{x + 2}{- x}

\frac{x ^{2} - 4}{9 x + 4}

\frac{2 x - 6}{x ^{2} + 2 x - 15}

What is the domain of y=(x^2-36)/(x+1) ?
The domain of y=(x^2-36)/(x+1) is x<-1\lor x>-1