What is the domain of g(x)=log_{3}(8-2x)+1 ?

The domain of g(x)=log_{3}(8-2x)+1 is x<4

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domain of g(x)=log_{3}(8-2x)+1

domain

g (x) = lo g_{3} (8 - 2 x) + 1

x < 4

Interval Notation

(- \infty, 4)

Solution steps

Find positive values for logs:

x < 4

The function domain

x < 4

f (x) = \frac{2 x + 4}{24 - 8 x}

f (x) = \frac{x + 2}{- x}

\frac{x ^{2} - 4}{9 x + 4}

\frac{2 x - 6}{x ^{2} + 2 x - 15}

f (x) = \frac{1}{x ^{2} - x - 12}

What is the domain of g(x)=log_{3}(8-2x)+1 ?
The domain of g(x)=log_{3}(8-2x)+1 is x<4