What is the domain of f(x)=sqrt(2cos(x)-1) ?

The domain of f(x)=sqrt(2cos(x)-1) is -pi/3+2pin<= x<= pi/3+2pin

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domain of f(x)=sqrt(2cos(x)-1)

domain

f (x) = 2 cos (x) - 1

- \frac{π}{3} + 2 πn \leq x \leq \frac{π}{3} + 2 πn

Interval Notation

[- \frac{π}{3} + 2 πn, \frac{π}{3} + 2 πn]

Solution steps

Find non-negative values for radicals:

- \frac{π}{3} + 2 πn \leq x \leq \frac{π}{3} + 2 πn

The function domain

- \frac{π}{3} + 2 πn \leq x \leq \frac{π}{3} + 2 πn

f (x) = \frac{8}{x - 3}

1 - lo g_{10} (x)

- x^{2} + 4 x + 5

\frac{5 x - 3}{1 - 4 x}

f (x) = x + \frac{x}{x ^{2} - 1}

What is the domain of f(x)=sqrt(2cos(x)-1) ?
The domain of f(x)=sqrt(2cos(x)-1) is -pi/3+2pin<= x<= pi/3+2pin