What is the domain of f(x)=((x-1)^2)/(x+1) ?

The domain of f(x)=((x-1)^2)/(x+1) is x -1

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domain of f(x)=((x-1)^2)/(x+1)

domain

f (x) = \frac{( x - 1 ) ^{2}}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = \frac{x}{1 - x}

f (x) = \frac{x - 1}{x ^{2} + 9}

f (x) = - x^{4} + x^{3} + 9 x

f (x) = lo g_{10} (2 x)

f (x) = (x^{2} - 3) e^{x}

What is the domain of f(x)=((x-1)^2)/(x+1) ?
The domain of f(x)=((x-1)^2)/(x+1) is x<-1\lor x>-1