What is the domain of f(x)=3ln(1+x)-x^2+4 ?

The domain of f(x)=3ln(1+x)-x^2+4 is x>-1

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domain of f(x)=3ln(1+x)-x^2+4

domain

f (x) = 3 ln (1 + x) - x^{2} + 4

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find positive values for logs:

x > - 1

The function domain

x > - 1

f (x) = \frac{3}{2 x - 18}

f (x) = \frac{8 cos ( x )}{1 - sin ( x )}

y = \frac{2}{( x - 3 ) ( x - 8 )}

- (1.1)^{x} + 1

∣ x ∣ + 2 x - 3

What is the domain of f(x)=3ln(1+x)-x^2+4 ?
The domain of f(x)=3ln(1+x)-x^2+4 is x>-1