What is the domain of f(x)=sqrt(-x^2+x+2) ?

The domain of f(x)=sqrt(-x^2+x+2) is -1<= x<= 2

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domain of f(x)=sqrt(-x^2+x+2)

domain

f (x) = - x^{2} + x + 2

- 1 \leq x \leq 2

Interval Notation

[- 1, 2]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 2

The function domain

- 1 \leq x \leq 2

f (x) = lo g_{3} ((1 + y)^{2})

f (x) = \frac{5}{x ^{2} - 16}

f (x) = lo g_{12} (15 - 24 x)

y = \frac{1}{x ^{2} - 4}

f (x) = x^{2} - 4 x + 4

What is the domain of f(x)=sqrt(-x^2+x+2) ?
The domain of f(x)=sqrt(-x^2+x+2) is -1<= x<= 2