What is the domain of f(x)=sqrt(4-t^2) ?

The domain of f(x)=sqrt(4-t^2) is -2<= t<= 2

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domain of f(x)=sqrt(4-t^2)

domain

f (x) = 4 - t^{2}

- 2 \leq t \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq t \leq 2

The function domain

- 2 \leq t \leq 2

y = x^{2} + 2 x + 4

f (x) = \frac{x - 3}{x ^{2} - 49}

lo g_{2} (x + 4)

g (x) = \frac{3}{x ^{2} - 2 x - 15}

- 4 n \cdot \frac{x ln ( x )}{1 - x}

What is the domain of f(x)=sqrt(4-t^2) ?
The domain of f(x)=sqrt(4-t^2) is -2<= t<= 2