What is the domain of f(x)= x/(sqrt(3x+9)) ?

The domain of f(x)= x/(sqrt(3x+9)) is x>-3

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domain of f(x)= x/(sqrt(3x+9))

domain

f (x) = \frac{x}{3 x + 9}

x > - 3

Interval Notation

(- 3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = - 3

Combine real regions and undefined points for final function domain

x > - 3

f (x) = \frac{2 x ^{2} + 3 x - 9}{2 x ^{2} - 32}

f (x) = e^{x^{3} + 1}

\frac{x ^{2} - 16}{x}

\frac{3 x}{x + 2}

f (x) = cos (t - 2)

What is the domain of f(x)= x/(sqrt(3x+9)) ?
The domain of f(x)= x/(sqrt(3x+9)) is x>-3