What is the domain of f(x)= x/((x^2-1)) ?

The domain of f(x)= x/((x^2-1)) is x 1

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domain of f(x)= x/((x^2-1))

domain

f (x) = \frac{x}{( x ^{2} - 1 )}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

\frac{x ^{2} + 6 x + 11}{x + 4}

f (x) = 4 - 4 - x^{2}

f (x) = x (x - 3) (x + 5)

\frac{- 3 x ^{2} + 3 x}{x + 1}

f (x) = x^{3} + 2 x - \frac{1}{x}

What is the domain of f(x)= x/((x^2-1)) ?
The domain of f(x)= x/((x^2-1)) is x<-1\lor-1<x<1\lor x>1