What is the domain of f(x)=sqrt(4-\sqrt{4-x^2)} ?

The domain of f(x)=sqrt(4-\sqrt{4-x^2)} is -2<= x<= 2

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domain of f(x)=sqrt(4-\sqrt{4-x^2)}

domain

f (x) = 4 - 4 - x^{2}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

f (x) = x (x - 3) (x + 5)

\frac{- 3 x ^{2} + 3 x}{x + 1}

f (x) = x^{3} + 2 x - \frac{1}{x}

f (x) = (x - 13) x^{2} + 4 x

f (x) = \frac{- 2 x ^{2}}{( x + 3 ) ( x - 5 )}

What is the domain of f(x)=sqrt(4-\sqrt{4-x^2)} ?
The domain of f(x)=sqrt(4-\sqrt{4-x^2)} is -2<= x<= 2