What is the domain of f(x)=(-2x^2)/((x+3)(x-5)) ?

The domain of f(x)=(-2x^2)/((x+3)(x-5)) is x 5

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domain of f(x)=(-2x^2)/((x+3)(x-5))

domain

f (x) = \frac{- 2 x ^{2}}{( x + 3 ) ( x - 5 )}

x < - 3 or - 3 < x < 5 or x > 5

Interval Notation

(- \infty, - 3) \cup (- 3, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = - 3, x = 5

The function domain

x < - 3 or - 3 < x < 5 or x > 5

f (x) = 1 - 1 - x

\frac{x ^{2} - 64}{5 x - 1}

- \frac{2}{3} sin (\frac{1}{3}) (y - \frac{3 π}{4}) + 2

x^{4} - 1

f (x) = (1 - x^{2})^{\frac{1}{3}}

What is the domain of f(x)=(-2x^2)/((x+3)(x-5)) ?
The domain of f(x)=(-2x^2)/((x+3)(x-5)) is x<-3\lor-3<x<5\lor x>5