What is the domain of f(x)=(1-x^2)^{1/3} ?

The domain of f(x)=(1-x^2)^{1/3} is -infinity <x<infinity

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domain of f(x)=(1-x^2)^{1/3}

domain

f (x) = (1 - x^{2})^{\frac{1}{3}}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

\frac{x}{ln ( x )}

f (x) = \frac{2 x - 1}{x ^{2} + 1}

\frac{x ^{2} - 64}{x ^{2} - 1}

y = 2 sin (2 x)

\frac{x ^{2} - 9}{x + 9}

What is the domain of f(x)=(1-x^2)^{1/3} ?
The domain of f(x)=(1-x^2)^{1/3} is -infinity <x<infinity