What is the domain of y= x/(x^2-1) ?

The domain of y= x/(x^2-1) is x 1

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domain of y= x/(x^2-1)

domain

y = \frac{x}{x ^{2} - 1}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = 16 x^{2} - 2

f (x) = \frac{3}{- 3 - x}

f (x) = \frac{2 x - 1}{x + 1}

2 x - 3 y + 4 x y - 7 = 0

f (x) = \frac{1}{2} x^{- \frac{2}{3}}

What is the domain of y= x/(x^2-1) ?
The domain of y= x/(x^2-1) is x<-1\lor-1<x<1\lor x>1