What is the domain of f(x)=(2x-1)/(x+1) ?

The domain of f(x)=(2x-1)/(x+1) is x -1

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domain of f(x)=(2x-1)/(x+1)

domain

f (x) = \frac{2 x - 1}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

2 x - 3 y + 4 x y - 7 = 0

f (x) = \frac{1}{2} x^{- \frac{2}{3}}

f (x) = (x - 1)^{2} - 4

f (x) = \frac{x + 1}{x ^{2} - 2 x - 15}

f (x) = \frac{1}{7.4 x - 8.3 x ^{2}}

What is the domain of f(x)=(2x-1)/(x+1) ?
The domain of f(x)=(2x-1)/(x+1) is x<-1\lor x>-1