What is the domain of g(x)=(sqrt(x-2))/(x-5) ?

The domain of g(x)=(sqrt(x-2))/(x-5) is 2 5

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domain of g(x)=(sqrt(x-2))/(x-5)

domain

g (x) = \frac{x - 2}{x - 5}

2 \leq x < 5 or x > 5

Interval Notation

[2, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

2 \leq x < 5 or x > 5

f (x) = (\frac{1}{2})^{3 x}

\frac{3}{x + 1} - 2

\frac{1}{( x + 2 )}

f (x) = \frac{2 x ^{2}}{x + 1}

f (x) = - 2^{x} + 3

What is the domain of g(x)=(sqrt(x-2))/(x-5) ?
The domain of g(x)=(sqrt(x-2))/(x-5) is 2<= x<5\lor x>5