What is the domain of f(x)=(1+x)/(sqrt(x-1)) ?

The domain of f(x)=(1+x)/(sqrt(x-1)) is x>1

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domain of f(x)=(1+x)/(sqrt(x-1))

domain

f (x) = \frac{1 + x}{x - 1}

x > 1

Interval Notation

(1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x > 1

\frac{x ^{2} - 4}{x - 4}

f (x) = x^{3} + 3 x^{2} - 4

f (x) = x - 2 + 4 - x

f (x) = \frac{x - 9}{x ^{2} - 16}

y = 4 x^{2} - 5 x + 10

What is the domain of f(x)=(1+x)/(sqrt(x-1)) ?
The domain of f(x)=(1+x)/(sqrt(x-1)) is x>1