What is the domain of f(x)=sqrt(x-2)+sqrt(4-x) ?

The domain of f(x)=sqrt(x-2)+sqrt(4-x) is 2<= x<= 4

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domain of f(x)=sqrt(x-2)+sqrt(4-x)

domain

f (x) = x - 2 + 4 - x

2 \leq x \leq 4

Interval Notation

[2, 4]

Solution steps

Find non-negative values for radicals:

2 \leq x \leq 4

The function domain

2 \leq x \leq 4

f (x) = \frac{x - 9}{x ^{2} - 16}

y = 4 x^{2} - 5 x + 10

f (x) = \frac{e ^{x} - 1}{e ^{x} + 1}

f (x) = \frac{x ^{2} - 4}{1 - x ^{2}}

f (x) = \frac{( 3 - x )}{( x + 2 )}

What is the domain of f(x)=sqrt(x-2)+sqrt(4-x) ?
The domain of f(x)=sqrt(x-2)+sqrt(4-x) is 2<= x<= 4