What is the domain of 1/(sqrt(18-3x-x^2)) ?

The domain of 1/(sqrt(18-3x-x^2)) is -6<x<3

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domain of 1/(sqrt(18-3x-x^2))

domain

\frac{1}{18 - 3 x - x ^{2}}

- 6 < x < 3

Interval Notation

(- 6, 3)

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 3

Find undefined (singularity) points:

x = - 6, x = 3

Combine real regions and undefined points for final function domain

- 6 < x < 3

f (x) = \frac{1}{( x + 5 ) ( x - 2 ) ( x - 7 )}

f (x) = - 1.1

\frac{6 + 7 x}{x - 1}

f (x) = \frac{- 6}{25 x ^{2} - 4}

f (x) = \frac{x}{4 - x} - \frac{2}{x ^{2} - 5 x}

What is the domain of 1/(sqrt(18-3x-x^2)) ?
The domain of 1/(sqrt(18-3x-x^2)) is -6<x<3