What is the domain of f(x)=(x*sqrt(10-x))/(2x-9) ?

The domain of f(x)=(x*sqrt(10-x))/(2x-9) is x< 9/2 \lor 9/2 <x<= 10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x*sqrt(10-x))/(2x-9)

domain

f (x) = \frac{x \cdot 10 - x}{2 x - 9}

x < \frac{9}{2} or \frac{9}{2} < x \leq 10

Interval Notation

(- \infty, \frac{9}{2}) \cup (\frac{9}{2}, 10]

Solution steps

Find non-negative values for radicals:

x \leq 10

Find undefined (singularity) points:

x = \frac{9}{2}

Combine real regions and undefined points for final function domain

x < \frac{9}{2} or \frac{9}{2} < x \leq 10

f (x) = - x - 5 + 1

x \cdot ln (x)

(1 + sin (x)) (1 + cos (x))

3 x^{\frac{2}{3}} - 2 x

f (x) = \frac{1}{2 x - 6}

What is the domain of f(x)=(x*sqrt(10-x))/(2x-9) ?
The domain of f(x)=(x*sqrt(10-x))/(2x-9) is x< 9/2 \lor 9/2 <x<= 10