What is the domain of f(x)= 1/(sqrt(2x-6)) ?

The domain of f(x)= 1/(sqrt(2x-6)) is x>3

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domain of f(x)= 1/(sqrt(2x-6))

domain

f (x) = \frac{1}{2 x - 6}

x > 3

Interval Notation

(3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 3

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x > 3

y = 2 x + 6

y = 2 x + 3

\frac{x - 1}{x ^{2} - 3 x + 2}

y = \frac{1}{4 - x ^{2}}

350000 \cdot csc (\frac{π}{30} x)

What is the domain of f(x)= 1/(sqrt(2x-6)) ?
The domain of f(x)= 1/(sqrt(2x-6)) is x>3