What is the domain of y=(x-1)/(x+1) ?

The domain of y=(x-1)/(x+1) is x -1

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domain of y=(x-1)/(x+1)

domain

y = \frac{x - 1}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

f (x) = \frac{3}{5 x - 1}

f (x) = lo g_{10} (3 x - 2)

f (x) = 2 ∣ x - 3 ∣ + 1

f (x) = t + 8

e^{2}

What is the domain of y=(x-1)/(x+1) ?
The domain of y=(x-1)/(x+1) is x<-1\lor x>-1