What is the domain of y=-sqrt(8x)+6 ?

The domain of y=-sqrt(8x)+6 is x>= 0

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domain of y=-sqrt(8x)+6

domain

y = - 8 x + 6

x \geq 0

Interval Notation

[0, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

The function domain

x \geq 0

f (x) = 3 x^{2} - 4 x^{3} - x + 1

13 - x

f (x) = \frac{( e ^{x} )}{1 + e ^{x}}

f (x) = \frac{x ^{2} - 9}{x + 1}

6 - x - x^{2}