What is the domain of f(x)=(x^2-9)/(x+1) ?

The domain of f(x)=(x^2-9)/(x+1) is x -1

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domain of f(x)=(x^2-9)/(x+1)

domain

f (x) = \frac{x ^{2} - 9}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

6 - x - x^{2}

f (x) = e^{x} + 2 x = 0

f (x) = \frac{x + 5}{x - 2}

f (x) = \frac{x + 2}{4 x - x ^{3}}

f (x) = \frac{1}{2 x - 1}

What is the domain of f(x)=(x^2-9)/(x+1) ?
The domain of f(x)=(x^2-9)/(x+1) is x<-1\lor x>-1