What is the domain of f(x)=-sqrt(5x^2-4) ?

The domain of f(x)=-sqrt(5x^2-4) is x = 2/(sqrt(5))

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domain of f(x)=-sqrt(5x^2-4)

domain

f (x) = - 5 x^{2} - 4

x \leq - \frac{2}{5} or x \geq \frac{2}{5}

Interval Notation

(- \infty, - \frac{2}{5}] \cup [\frac{2}{5}, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - \frac{2}{5} or x \geq \frac{2}{5}

The function domain

x \leq - \frac{2}{5} or x \geq \frac{2}{5}

f (x) = 3 - 4 - x^{2}

f (x) = e^{x} + e^{- x}

\frac{2 ^{4 x - 1} \cdot 3 ^{x - 2}}{1 2 ^{x - 2}}

lo g_{2} (x^{2} - 1)

ln (2 t - 1)

What is the domain of f(x)=-sqrt(5x^2-4) ?
The domain of f(x)=-sqrt(5x^2-4) is x<=-2/(sqrt(5))\lor x>= 2/(sqrt(5))