What is the domain of f(x)=sqrt(x-2)+\sqrt[4]{8-x} ?

The domain of f(x)=sqrt(x-2)+\sqrt[4]{8-x} is 2<= x<= 8

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domain of f(x)=sqrt(x-2)+\sqrt[4]{8-x}

domain

2 \leq x \leq 8

Interval Notation

[2, 8]

Solution steps

Find non-negative values for radicals:

2 \leq x \leq 8

The function domain

2 \leq x \leq 8

f (x) = x + 2 - lo g_{3} (2 - x)

y = \frac{x + 1}{x - 1}

\frac{9}{7 x - 2}

f (x) = lo g_{10} (x) - 3

\frac{2 x - 6}{x - 4}

What is the domain of f(x)=sqrt(x-2)+\sqrt[4]{8-x} ?
The domain of f(x)=sqrt(x-2)+\sqrt[4]{8-x} is 2<= x<= 8