What is the domain of sqrt(1/(x^2+4)) ?

The domain of sqrt(1/(x^2+4)) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of sqrt(1/(x^2+4))

domain

\frac{1}{x ^{2} + 4}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{x - 5}{x ^{2} - 9}

\frac{2 ∣ x ∣ - x}{2 ∣ x ∣ + x}

f (x) = (ln (t + 1))

f (x) = \frac{- 4}{3 x} + \frac{1}{3 ( x - 3 )}

f (x) = \frac{8 x + 2}{6 x + 6}

What is the domain of sqrt(1/(x^2+4)) ?
The domain of sqrt(1/(x^2+4)) is -infinity <x<infinity