What is the domain of f(x)=sqrt((x-3)/(x+4)) ?

The domain of f(x)=sqrt((x-3)/(x+4)) is x = 3

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domain of f(x)=sqrt((x-3)/(x+4))

domain

f (x) = \frac{x - 3}{x + 4}

x < - 4 or x \geq 3

Interval Notation

(- \infty, - 4) \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x < - 4 or x \geq 3

Find undefined (singularity) points:

x = - 4

Combine real regions and undefined points for final function domain

x < - 4 or x \geq 3

1 + \frac{1}{x} - \frac{1}{x ^{2}}

f (x) = 4 - 2 x^{2}

f (x) = x^{4} - 6 x^{2}

f (x) = arccosh (x)

\frac{x ^{2} + 1}{x ^{2} - x + 1}

What is the domain of f(x)=sqrt((x-3)/(x+4)) ?
The domain of f(x)=sqrt((x-3)/(x+4)) is x<-4\lor x>= 3