What is the domain of f(x)= 1/(|x^2-4|) ?

The domain of f(x)= 1/(|x^2-4|) is x 2

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domain of f(x)= 1/(|x^2-4|)

domain

f (x) = \frac{1}{∣ x ^{2} - 4 ∣}

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = - 2, x = 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

x^{3} + 4 x

f (x) = \frac{2 x}{x ^{2} - x - 2}

f (x) = \frac{x ( x - 3 ) - 1}{4}

x^{2} - 7 x + 6

f (x) = lo g_{10} (8 - 5 x)

What is the domain of f(x)= 1/(|x^2-4|) ?
The domain of f(x)= 1/(|x^2-4|) is x<-2\lor-2<x<2\lor x>2