What is the domain of f(x)=sqrt(6-x)+sqrt(x-2) ?

The domain of f(x)=sqrt(6-x)+sqrt(x-2) is 2<= x<= 6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(6-x)+sqrt(x-2)

domain

f (x) = 6 - x + x - 2

2 \leq x \leq 6

Interval Notation

[2, 6]

Solution steps

Find non-negative values for radicals:

2 \leq x \leq 6

The function domain

2 \leq x \leq 6

f (x) = \frac{2}{x - 8}

f (x) = \frac{x + 8}{( x - 4 ) ( x + 6 )}

\frac{2 x - 3}{x + 1}

\frac{x - 4}{2 x ^{2} + 8 x}

\frac{3 x - 2}{x + 5}

What is the domain of f(x)=sqrt(6-x)+sqrt(x-2) ?
The domain of f(x)=sqrt(6-x)+sqrt(x-2) is 2<= x<= 6